锟竭讹拷锟斤拷(sh锟斤拷)锟絎(xu锟斤拷)锟斤拷(f锟斤拷)锟斤拷(x锟斤拷)锟斤拷锟斤拷锟斤拷锟斤拷锟角猴拷锟斤拷(sh锟斤拷)知锟絉(sh锟斤拷)锟絚(di锟斤拷n)
2022-08-10 17:07:51锟竭匡拷锟絎(w锟斤拷ng)锟斤拷锟斤拷
锟斤拷锟斤拷锟絁锟斤拷锟斤拷锟角猴拷锟斤拷(sh锟斤拷)锟斤拷锟絰
锟斤拷锟斤拷锟絁锟角斤拷A锟斤拷锟斤拷锟斤拷(sin),锟斤拷锟斤拷(cos)锟斤拷锟斤拷锟斤拷(tan),锟斤拷锟斤拷(cot)锟皆硷拷锟斤拷锟斤拷(sec)锟斤拷锟斤拷锟(csc)锟斤拷锟斤拷锟斤拷锟斤拷A锟斤拷锟絁锟斤拷锟斤拷锟角猴拷锟斤拷(sh锟斤拷)锟斤拷
锟斤拷锟斤拷锟斤拷锟斤拷(sin)锟斤拷锟节岋拷邊锟斤拷斜邊;sinA=a/c
锟斤拷锟斤拷锟斤拷锟斤拷(cos)锟斤拷锟斤拷锟斤拷邊锟斤拷斜邊;cosA=b/c
锟斤拷锟斤拷锟斤拷锟斤拷(tan)锟斤拷锟节岋拷邊锟斤拷锟斤拷邊;tanA=a/b
锟斤拷锟斤拷锟斤拷锟斤拷(cot)锟斤拷锟斤拷锟斤拷邊锟饺岋拷邊;cotA=b/a
锟斤拷锟斤拷锟斤拷锟斤拷(sec)锟斤拷锟斤拷斜邊锟斤拷锟斤拷邊;secA=c/b
锟斤拷锟斤拷锟斤拷锟(csc)锟斤拷锟斤拷斜邊锟饺岋拷邊锟斤拷cscA=c/a
锟斤拷锟斤拷锟斤拷锟斤拷堑锟斤拷锟斤拷呛锟斤拷锟(sh锟斤拷)锟絞锟斤拷锟絇(gu锟斤拷n)系
锟斤拷锟斤拷sin(90°-α)=cosα, cos(90°-α)=sinα,
锟斤拷锟斤拷tan(90°-α)=cotα, cot(90°-α)=tanα.
锟斤拷锟斤拷平锟斤拷锟絇(gu锟斤拷n)系锟斤拷
锟斤拷锟斤拷sin^2(α)+cos^2(α)=1
锟斤拷锟斤拷tan^2(α)+1=sec^2(α)
锟斤拷锟斤拷cot^2(α)+1=csc^2(α)
锟斤拷锟斤拷锟絜锟斤拷锟絇(gu锟斤拷n)系锟斤拷
锟斤拷锟斤拷sinα=tanα·cosα
锟斤拷锟斤拷cosα=cotα·sinα
锟斤拷锟斤拷tanα=sinα·secα
锟斤拷锟斤拷cotα=cosα·cscα
锟斤拷锟斤拷secα=tanα·cscα
锟斤拷锟斤拷cscα=secα·cotα
锟斤拷锟斤拷锟斤拷锟斤拷(sh锟斤拷)锟絇(gu锟斤拷n)系锟斤拷
锟斤拷锟斤拷tanα·cotα=1
锟斤拷锟斤拷sinα·cscα=1
锟斤拷锟斤拷cosα·secα=1
锟斤拷锟斤拷锟絁锟斤拷锟斤拷锟角猴拷锟斤拷(sh锟斤拷)锟斤拷式
锟斤拷锟斤拷锟缴角猴拷锟絚锟斤拷锟斤拷锟斤拷呛锟斤拷锟(sh锟斤拷)锟斤拷
锟斤拷锟斤拷sin(A+B) = sinAcosB+cosAsinB
锟斤拷锟斤拷sin(A-B) = sinAcosB-cosAsinB ?
锟斤拷锟斤拷cos(A+B) = cosAcosB-sinAsinB
锟斤拷锟斤拷cos(A-B) = cosAcosB+sinAsinB
锟斤拷锟斤拷tan(A+B) = (tanA+tanB)/(1-tanAtanB)
锟斤拷锟斤拷tan(A-B) = (tanA-tanB)/(1+tanAtanB)
锟斤拷锟斤拷cot(A+B) = (cotAcotB-1)/(cotB+cotA)
锟斤拷锟斤拷cot(A-B) = (cotAcotB+1)/(cotB-cotA)
锟斤拷锟斤拷锟斤拷锟角和碉拷锟斤拷锟角猴拷锟斤拷(sh锟斤拷)锟斤拷
锟斤拷锟斤拷sin(α+β+γ)=sinα·cosβ·cosγ+cosα·sinβ·cosγ+cosα·cosβ·sinγ-sinα·sinβ·sinγ
锟斤拷锟斤拷cos(α+β+γ)=cosα·cosβ·cosγ-cosα·sinβ·sinγ-sinα·cosβ·sinγ-sinα·sinβ·cosγ
锟斤拷锟斤拷tan(α+β+γ)=(tanα+tanβ+tanγ-tanα·tanβ·tanγ)/(1-tanα·tanβ-tanβ·tanγ-tanγ·tanα)
锟斤拷锟斤拷锟給锟斤拷锟角癸拷式锟斤拷
锟斤拷锟斤拷Asinα+Bcosα=(A^2+B^2)^(1/2)sin(α+t)锟斤拷锟斤拷锟斤拷
锟斤拷锟斤拷sint=B/(A^2+B^2)^(1/2)
锟斤拷锟斤拷cost=A/(A^2+B^2)^(1/2)
锟斤拷锟斤拷tant=B/A
锟斤拷锟斤拷Asinα+Bcosα=(A^2+B^2)^(1/2)cos(α-t)锟斤拷tant=A/B
锟斤拷锟斤拷锟斤拷锟角癸拷式锟斤拷
锟斤拷锟斤拷sin(2α)=2sinα·cosα=2/(tanα+cotα)
锟斤拷锟斤拷cos(2α)=cos^2(α)-sin^2(α)=2cos^2(α)-1=1-2sin^2(α)
锟斤拷锟斤拷tan(2α)=2tanα/[1-tan^2(α)]
锟斤拷锟斤拷锟斤拷锟斤拷锟角癸拷式锟斤拷
锟斤拷锟斤拷sin(3α)=3sinα-4sin^3(α)
锟斤拷锟斤拷cos(3α)=4cos^3(α)-3cosα
锟斤拷锟斤拷锟斤拷枪锟绞斤拷锟
锟斤拷锟斤拷sin(α/2)=±√((1-cosα)/2)
锟斤拷锟斤拷cos(α/2)=±√((1+cosα)/2)
锟斤拷锟斤拷tan(α/2)=±√((1-cosα)/(1+cosα))=sinα/(1+cosα)=(1-cosα)/sinα
锟斤拷锟斤拷锟斤拷锟界公式锟斤拷
锟斤拷锟斤拷sin^2(α)=(1-cos(2α))/2=versin(2α)/2
锟斤拷锟斤拷cos^2(α)=(1+cos(2α))/2=covers(2α)/2
锟斤拷锟斤拷tan^2(α)=(1-cos(2α))/(1+cos(2α))
锟斤拷锟斤拷锟斤拷锟絇(gu锟斤拷n)锟斤拷锟絔锟斤拷
锟竭讹拷锟斤拷(sh锟斤拷)锟絎(xu锟斤拷)锟斤拷(f锟斤拷)锟斤拷(x锟斤拷)锟斤拷锟斤拷锟絉锟斤拷
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