2025锟斤拷呖锟斤拷锟斤拷袛锟(sh锟斤拷)锟絎(xu锟斤拷) 锟斤拷锟角猴拷锟斤拷(sh锟斤拷)锟斤拷式锟斤拷全
2024-08-18 16:27:02锟絎(w锟斤拷ng)锟絡(lu锟斤拷)锟斤拷锟斤拷
锟斤拷锟叫旓拷(sh锟斤拷)锟絎(xu锟斤拷) 锟斤拷锟角猴拷锟斤拷(sh锟斤拷)锟斤拷式锟斤拷全
锟斤拷锟角猴拷锟斤拷(sh锟斤拷)锟紷锟铰癸拷式锟杰讹拷锟斤拷锟斤拷锟斤拷锟斤拷锟絋锟斤拷(d锟斤拷o)锟斤拷式锟斤拷锟叫讹拷十锟斤拷锟斤拷(g锟斤拷)锟斤拷全锟斤拷記锟斤拷锟角憋拷锟絕锟斤拷锟斤拷锟斤拷锟斤拷锟紸(ch锟斤拷)锟斤拷锟斤拷同锟絎(xu锟斤拷)锟斤拷锟斤拷(y锟斤拷ng)該锟矫猴拷記記锟紷些锟斤拷式锟斤拷锟届練锟紷些锟斤拷式也锟斤拷抓住锟斤拷锟紷锟铰碉拷锟斤拷锟絚(di锟斤拷n)锟剿★拷锟斤拷(f锟斤拷)锟斤拷(x锟斤拷)锟斤拷锟斤拷(l锟斤拷i)锟铰半功锟斤拷锟斤拷
锟缴角猴拷
sin(A+B)=sinAcosB+cosAsinB sin(A-B)=sinAcosB-sinBcosA cos(A+B)=cosAcosB-sinAsinB cos(A-B)=cosAcosB+sinAsinB tan(A+B)=(tanA+tanB)/(1-tanAtanB) tan(A-B)=(tanA-tanB)/(1+tanAtanB) cot(A+B)=(cotAcotB-1)/(cotB+cotA) cot(A-B)=(cotAcotB+1)/(cotB-cotA)
2锟斤拷锟斤拷
tan2A=2tanA/(1-tan2A) cot2A=(cot2A-1)/2cota cos2a=cos2a-sin2a=2cos2a-1=1-2sin2a sinα+sin(α+2π/n)+sin(α+2π*2/n)+sin(α+2π*3/n)+……+sin[α+2π*(n-1)/n]=0 cosα+cos(α+2π/n)+cos(α+2π*2/n)+cos(α+2π*3/n)+……+cos[α+2π*(n-1)/n]=0 锟皆硷拷 sin^2(α)+sin^2(α-2π/3)+sin^2(α+2π/3)=3/2 tanAtanBtan(A+B)+tanA+tanB-tan(A+B)=0
锟侥憋拷锟斤拷
sin4A=-4*(cosA*sinA*(2*sinA^2-1)) cos4A=1+(-8*cosA^2+8*cosA^4) tan4A=(4*tanA-4*tanA^3)/(1-6*tanA^2+tanA^4)
锟藉倍锟斤拷
sin5A=16sinA^5-20sinA^3+5sinA cos5A=16cosA^5-20cosA^3+5cosA tan5A=tanA*(5-10*tanA^2+tanA^4)/(1-10*tanA^2+5*tanA^4)
锟斤拷锟斤拷锟斤拷
sin6A=2*(cosA*sinA*(2*sinA+1)*(2*sinA-1)*(-3+4*sinA^2)) cos6A=((-1+2*cosA^2)*(16*cosA^4-16*cosA^2+1))tan6A=(-6*tanA+20*tanA^3-6*tanA^5)/(-1+15*tanA^2-15*tanA^4+tanA^6)
锟竭憋拷锟斤拷
sin7A=-(sinA*(56*sinA^2-112*sinA^4-7+64*sinA^6)) cos7A=(cosA*(56*cosA^2-112*cosA^4+64*cosA^6-7)) tan7A=tanA*(-7+35*tanA^2-21*tanA^4+tanA^6)/(-1+21*tanA^2-35*tanA^4+7*tanA^6)
锟剿憋拷锟斤拷
sin8A=-8*(cosA*sinA*(2*sinA^2-1)*(-8*sinA^2+8*sinA^4+1)) cos8A=1+(160*cosA^4-256*cosA^6+128*cosA^8-32*cosA^2) tan8A=-8*tanA*(-1+7*tanA^2-7*tanA^4+tanA^6)/(1-28*tanA^2+70*tanA^4-28*tanA^6+tanA^8)
锟脚憋拷锟斤拷
sin9A=(sinA*(-3+4*sinA^2)*(64*sinA^6-96*sinA^4+36*sinA^2-3)) cos9A=(cosA*(-3+4*cosA^2)*(64*cosA^6-96*cosA^4+36*cosA^2-3)) tan9A=tanA*(9-84*tanA^2+126*tanA^4-36*tanA^6+tanA^8)/(1-36*tanA^2+126*tanA^4-84*tanA^6+9*tanA^8)
十锟斤拷
(sin10A=2*(cosA*sinA*(4*sinA^2+2*sinA-1)*(4*sinA^2-2*sinA-1)*(-20*sinA^2+5+16*sinA^4))
cos10A=((-1+2*cosA^2)*(256*cosA^8-512*cosA^6+304*cosA^4-48*cosA^2+1))
tan10A=-2*tanA*(5-60*tanA^2+126*tanA^4-60*tanA^6+5*tanA^8)/(-1+45*tanA^2-210*tanA^4+210*tanA^6-45*tanA^8+tanA^10)
锟絝(w锟斤拷n)锟杰癸拷式
sinα=2tan(α/2)/[1+tan^2(α/2)]
cosα=[1-tan^2(α/2)]/[1+tan^2(α/2)]
tanα=2tan(α/2)/[1-tan^2(α/2)]
锟斤拷锟
sin(A/2)=√((1-cosA)/2) sin(A/2)=-√((1-cosA)/2)
cos(A/2)=√((1+cosA)/2) cos(A/2)=-√((1+cosA)/2)
tan(A/2)=√((1-cosA)/((1+cosA)) tan(A/2)=-√((1-cosA)/((1+cosA))
cot(A/2)=√((1+cosA)/((1-cosA)) cot(A/2)=-√((1+cosA)/((1-cosA))
锟酵差化锟絜
2sinAcosB=sin(A+B)+sin(A-B) 2cosAsinB=sin(A+B)-sin(A-B)
2cosAcosB=cos(A+B)-sin(A-B) -2sinAsinB=cos(A+B)-cos(A-B)
sinA+sinB=2sin((A+B)/2)cos((A-B)/2 cosA+cosB=2cos((A+B)/2)sin((A-B)/2)
tanA+tanB=sin(A+B)/cosAcosB tanA-tanB=sin(A-B)/cosAcosB
cotA+cotBsin(A+B)/sinAsinB -cotA+cotBsin(A+B)/sinAsinB
锟斤拷锟絇(gu锟斤拷n)锟斤拷锟絔锟斤拷
锟斤拷锟斤拷锟竭匡拷锟斤拷(sh锟斤拷)锟絎(xu锟斤拷)锟斤拷(f锟斤拷)锟斤拷(x锟斤拷)锟斤拷锟斤拷
锟斤拷锟铰高匡拷锟結訊锟斤拷锟竭匡拷锟斤拷锟斤拷锟斤拷锟斤拷前锟斤拷(zh锟斤拷n)锟斤拷锟斤拷志愿锟斤拷锟(b锟斤拷o)锟斤拷锟饺★拷锟?j锟斤拷n)?sh锟斤拷)锟斤拷锟斤拷
锟竭匡拷锟絩(sh锟斤拷)锟絞锟斤拷锟斤拷全锟斤拷锟斤拷要锟斤拷(ji锟斤拷)锟絚(di锟斤拷n)
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